Radian measure, converting degrees and radians, arc length and sector area formulae.
Answer at least 3 of 3 correctly to complete this section.
At GCSE you measured angles in degrees. At A-Level, you switch to radians — and for good reason.
Here is the key result that motivates the entire switch. When θ is measured in radians:
limθ→0θsinθ=1
This limit is only true in radians. In degrees, limθ→0θsinθ°=180π≈0.01745. This limit is the reason that dxd(sinx)=cosx — only when x is in radians. If you used degrees, every derivative and integral involving trig would carry an extra factor of 180π. Radians eliminate this entirely.
Beyond calculus, radians make the formulae for arc length and sector area far simpler. Radians are not just an alternative to degrees — they are the natural unit of angle measurement, defined directly from the geometry of the circle. Every A-Level topic from here on — trig equations, calculus, series — assumes you are working in radians.
One radian is the angle subtended at the centre of a circle by an arc equal in length to the radius.
Since the circumference of a circle is 2πr, the number of radius-lengths that fit around the full circle is 2π. Therefore:
2π radians=360°andπ radians=180°
This gives us the conversion factors:
1°=180π radand1 rad=π180°
Use the explorer below to see the connection between the angle, the point on the unit circle, and the sine/cosine wave:
Key angle — exact values shown.
| Degrees | Radians |
|---|---|
| 0° | 0 |
| 30° | 6π |
| 45° | 4π |
| 60° | 3π |
| 90° | 2π |
| 180° | π |
| 270° | 23π |
| 360° | 2π |
Memory trick: The “nice” angles in degrees (30, 45, 60, 90) become 6π,4π,3π,2π — notice the denominators go 6, 4, 3, 2 (decreasing).
Convert 150° to radians.
150°=150×180π=180150π=65π
Convert 47π radians to degrees.
47π×π180°=47×180°=315°
Answer at least 3 of 3 correctly to complete this section.
When θ is in radians, the arc length formula is beautifully simple:
s=rθ
Compare this with the degree version s=180πrθ — the radian version has no constants to remember.
This formula is actually the definition of a radian in disguise. If θ=1 radian, then s=r — the arc length equals the radius.
The area of a sector with angle θ (in radians) is:
A=21r2θ
Where does this come from? A sector with angle θ is the fraction 2πθ of the full circle. So the area is 2πθ×πr2=21r2θ.
A sector of a circle with radius 8 cm has an angle of 3π radians. Find the arc length and the area of the sector.
Arc length:
s=rθ=8×3π=38π cm
Area:
A=21r2θ=21×64×3π=332π cm2
A sector has radius 5 cm and arc length 12 cm. Find the angle of the sector in radians.
Using s=rθ:
θ=rs=512=2.4 radians
Note: Not all radian answers are neat multiples of π. When a question gives numerical values (not in terms of π), expect a decimal answer.
Answer at least 3 of 3 correctly to complete this section.
A segment is the region between a chord and the arc it cuts off. To find its area, subtract the triangle from the sector.
Segment area=Sector area−Triangle area
=21r2θ−21r2sinθ
=21r2(θ−sinθ)
Where does the triangle area come from? The triangle formed by the two radii and the chord has sides r, r, with included angle θ. Using the formula Area=21absinC, we get 21r2sinθ.
A chord of a circle with radius 10 cm subtends an angle of 32π radians at the centre. Find the area of the minor segment.
Sector area:
21×100×32π=3100π
Triangle area:
21×100×sin32π=50×23=253
Segment area:
3100π−253≈104.7−43.3=61.4 cm2
For the same circle and angle as above, find the perimeter of the minor segment.
The perimeter consists of the arc and the chord.
Arc length: s=10×32π=320π
Chord length (using the cosine rule or 2rsin2θ):
chord=2×10×sin3π=20×23=103
Perimeter:
320π+103≈20.9+17.3=38.2 cm
Answer at least 3 of 3 correctly to complete this section.
You already know these values from your work in degrees. Now test yourself in radians — no peeking at the table from the Trig Identities lesson.
Fill in the blanks:
Answers: 22, 23, 3, 21, 22. If you got all five without looking, you are ready for A-Level trig. If not, practise until these are automatic.
You must be equally comfortable working with these in radians as you are in degrees. From this point on, most A-Level questions will use radians.
The diagram shows a sector OAB of a circle with centre O, radius 12 cm, and angle 3π radians. Find: (a) the perimeter of the sector (b) the area of the shaded segment
(a) Perimeter of sector:
Perimeter=2r+s=2(12)+12×3π=24+4π cm
(b) Segment area:
21×144×(3π−sin3π)=72(3π−23)=24π−363 cm2
Answer at least 3 of 4 correctly to complete this section.
Lock in what you've learned with exam-style questions and spaced repetition.